codeigniter, result() vs. result_array()

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I use both result() and result_array().

Usually i like to get my result as array thats why i use result_array() mostly..

But i want to know which is the better approach that i should follow, Which one of them is more efficient to use in regards to performance?

Here is the Example i am talking about in codeigniter queries

$query = $this->db->get();
$result = $query->result_array();

or is this should be the better approach??

$query = $this->db->get();
$result = $query->result();

also right now i am using result_array in my generic model.

Answers

Result has an optional $type parameter which decides what type of result is returned. By default ($type = "object"), it returns an object (result_object()). It can be set to "array", then it will return an array of result, that being equivalent of caling result_array(). The third version accepts a custom class to use as a result object.

The code from CodeIgniter:

/**
* Query result. Acts as a wrapper function for the following functions.
*
* @param string $type 'object', 'array' or a custom class name
* @return array
*/
public function result($type = 'object')
{
    if ($type === 'array')
    {
        return $this->result_array();
    }
    elseif ($type === 'object')
    {
        return $this->result_object();
    }
    else
    {
        return $this->custom_result_object($type);
    }
}

Arrays are technically faster, but they are not objects. It depends where do you want to use the result. Most of the time, arrays are sufficient.

Tuesday, September 6, 2022

kameleon40-6aae7aa45624

Hm, understand. As I see the subquery's source code in line 27, it wants to call _compile_select or get_compiled_select. If you can check in CI's DB_active_rec.php the _compile_select is protected so you can't access from Subquery (it isn't subclass of db).

Possible solution: _compile_select() should public or class Subquery should be extend of CI's db class. I think you should report this to author of Subquery.

Or you can extend the CI's db class :)

Sorry - I want to write it as a comment.

Sunday, December 18, 2022

ghazi

Try this code it might help you :

Here dashboard is the name of controller

//this will route as localhost/appFolder/admin/index
  $route['admin'] = 'dashboard'; // for your index page

//this will route as localhost/appFolder/admin/method_name
 $route['admin/(:any)'] = 'dashboard/$1';

//this will route as localhost/appFolder/admin/method_name/param1
$route['admin/(:any)/(:any)'] = 'dashboard/$1/$2';

Link the route Like

// for your index page
<a href="<?php echo base_url('admin/index'); ?>"></a>

// for your other pages
<a href="<?php echo base_url('admin/method_name'); ?>"></a>

To link the other controller defined just like

 <a href="<?php echo base_url('otherControllerName/method_name'); ?>"></a>

Sunday, September 4, 2022

dieter_hubau

You got to use pagination() function without get() or getResult() and note that it is a function from the Model class your custom model extend from. So you should call it directly from the model, not from $this->db (this is why he doesn't know it).

This should be the function in your model :

public function brand_name($brand_name_slug)
    {
        return $this
                    ->table('shop a')
                    ->select()
                    ->join('(SELECT sku, MIN(sale_price) AS sale_price FROM shop GROUP BY sku) AS b', 'a.sku = b.sku AND a.sale_price = b.sale_price')
                    ->where('availability', 'in stock')
                    ->where('a.sku !=', '')
                    ->where('brand_name_slug', $brand_name_slug)
                    ->groupBy('a.sku')
                    ->orderBy('brand_name, subbrand_name, product, size, unit')
                    ->paginate(10);
    }

And $data in your controller :

$data = [
            'category_menu' => $model->category_menu(),
            'brand_menu' => $model->brand_menu(),
            'nav' => $model->nav(),
            'subnav' => $model->subnav(),
            'shop' => $model->brand_name($brand_name_slug),
            'pager' => $model->pager
        ];

Saturday, December 10, 2022

njames

According the the page you referenced, the Active Record class uses mysql_ functions for string-escaping. That means it's still building SQL strings up in PHP-land instead of using parametrized APIs into the database. While it may be free of known defects right now, it is still a better idea to use an API that follows a more secure design.

Wednesday, August 17, 2022

yashwanth_kumar

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