in the string

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I was wondering how I could check a string broken into an array against a preg_match to see if it started with www. I already have one that check for http://www.

function isValidURL($url)
{
return preg_match('|^http(s)?://[a-z0-9-]+(.[a-z0-9-]+)*(:[0-9]+)?(/.*)?$|i', $url);
}

$stringToArray = explode(" ",$_POST['text']);

  foreach($stringToArray as $key=>$val){
  $urlvalid = isValidURL($val);
  if($urlvalid){
  $_SESSION["messages"][] = "NO URLS ALLOWED!";
  header("Location: http://www.domain.com/post/id/".$_POST['postID']);
     exit();
     }
     }

Thanks! Stefan

Answers

You want something like:

%^((https?://)|(www.))([a-z0-9-].?)+(:[0-9]+)?(/.*)?$%i

this is using the | to match either http:// or www at the beginning. I changed the delimiter to % to avoid clashing with the |

Monday, October 24, 2022

emrekarahan0001-63c8236f938d

Try this:

preg_match("#b(([w-]+://?|www[.])[^s()<>]+(?:([wd]+)|([^[:punct:]s]|/)))#i", $text, $matches);

You were missing the regex delimiters (usually /, but using # here because it's more convenient for URLs)

Tuesday, December 27, 2022

pavel_strakhov

[Edited (again) to improve formatting and fix the intro.]

This is a comment and an answer.

The answer part... I do agree with alex' earlier answer.

(?: ), in contrast to ( ), is used to avoid capturing text, generally so as to have fewer back references thrown in with those you do want or to improve speed performance.
The ? following the (?: ) -- or when following anything except * + ? or {} -- means that the preceding item may or may not be found within a legitimate match. Eg, /z34?/ will match z3 as well as z34 but it won't match z35 or z etc.

The comment part... I made what might considered to be improvements to the regex you were working on:

(?:^|s)(0?[1-9]|[1-2][0-9]|30|31)-(0?[1-9]|10|11|12)-((?:20)?[0-9][0-9])(?:s|$)

-- First, it avoids things like 0-0-2011

-- Second, it avoids things like 233443-4-201154564

-- Third, it includes things like 1-1-2022

-- Forth, it includes things like 1-1-11

-- Fifth, it avoids things like 34-4-11

-- Sixth, it allows you to capture the day, month, and year so you can refer to these more easily in code.. code that would, for example, do a further check (is the second captured group 2 and is either the first captured group 29 and this a leap year or else the first captured group is <29) in order to see if a feb 29 date qualified or not.

Finally, note that you'll still get dates that won't exist, eg, 31-6-11. If you want to avoid these, then try:

(?:^|s)(?:(?:(0?[1-9]|[1-2][0-9]|30|31)-(0?[13578]|10|12))|(?:(0?[1-9]|[1-2][0-9]|30)-(0?[469]|11))|(?:(0?[1-9]|[1-2][0-9])-(0?2)))-((?:20)?[0-9][0-9])(?:s|$)

Also, I assumed the dates would be preceded and followed by a space (or beg/end of line), but you may want ot adjust that (eg, to allow punctuations).

A commenter elsewhere referenced this resource which you might find useful: http://rubular.com/

Sunday, December 4, 2022

tawfekov

The quickest way is to use NSString's +stringWithContentsOfURL: method. However, this is a modal call, and your application will be non-responsive while it runs. You can either move it to a background thread, or use the NSURLConnection class to make a proper, asynchronous request.

Friday, September 30, 2022

shadab.tughlaq

function qry(sr) {
  var qa = [];
  for (var prs of sr.split('&')) {
    var pra = prs.split('=');
    qa[pra[0]] = pra[1];
  }
  return qa;
}

var z = qry('http://example.com/product.php?action=edit&id=c23_02398105&side=1');
z.id; // c23_02398105

Source

Tuesday, November 22, 2022

daneoshiga

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