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Number of seconds from now() to Sunday midnight
Calculates difference between two dates in PHP

Hello All,

In my project, I need to calculate the difference in seconds between two dates:

For Example :

$firstDay = "2011-05-12 18:20:20";
$secondDay = "2011-05-13 18:20:20";

Then I should get 86400 Seconds That is 24 hours.

Similarly For

$firstDay = "2011-05-13 11:59:20";
$secondDay = "2011-05-13 12:00:20";

It should return 60 Seconds.

I read lots of questions in the But they only deals with the difference between 2 minute fields like 11:50:01 and 12:10:57


$timeFirst  = strtotime('2011-05-12 18:20:20');
$timeSecond = strtotime('2011-05-13 18:20:20');
$differenceInSeconds = $timeSecond - $timeFirst;

You will then be able to use the seconds to find minutes, hours, days, etc.

Wednesday, November 23, 2022

you need to escape the a and t as both have special meaning when used as formatting options in date()

echo date('M j at h:i a');

See it in action

Monday, October 17, 2022

You don't need to change the php.ini file if you use date_default_timezone_set(). Just set it to the timezone you will be working in.

Something like this should go in a config file or on the page where you're working with dates (if it is only one page):

Friday, December 23, 2022

You can turn a date object into a long (milliseconds since Jan 1, 1970), and then use TimeUnit to get the number of seconds:

long diffInMs = endDate.getTime() - startDate.getTime();

long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMs);

Edit: -Corrected the name of the variable diffInMs which was written diffInM(i)s in the second line.

Friday, December 23, 2022

First figure how many days there are between the two dates. Divide the number of days by 7 to get full weeks.

Now figure out if there's an extra week to be counted by finding taking the number of days modulus 7 to get any remaining days. If the first date plus remaining days falls in a different week, add an extra week on to the count.

void Main()

    var first = new DateTime(2018, 04, 13);
    var second = new DateTime(2018, 04, 16);

    Console.WriteLine(weekDiff(first, second));

public int weekDiff(DateTime d1, DateTime d2, DayOfWeek startOfWeek = DayOfWeek.Monday)
    var diff = d2.Subtract(d1);

    var weeks = (int)diff.Days / 7;

    // need to check if there's an extra week to count
    var remainingDays = diff.Days % 7;
    var cal = CultureInfo.InvariantCulture.Calendar;
    var d1WeekNo = cal.GetWeekOfYear(d1, CalendarWeekRule.FirstFullWeek, startOfWeek);
    var d1PlusRemainingWeekNo = cal.GetWeekOfYear(d1.AddDays(remainingDays), CalendarWeekRule.FirstFullWeek, startOfWeek);

    if (d1WeekNo != d1PlusRemainingWeekNo)

    return weeks;
Sunday, October 23, 2022
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