Get filename of file which ran PHP include

If you need to determine the base path of a set of scripts, you should not rely on the "current working directory." This can change from executing environment to executing environment.

Instead, base it on a known path.

/includes/class_bootstrap.php knows that it's going to be one directory down from where the base path is going to be, so it can do this:

define('CWD', realpath(dirname(__FILE__) . '/../') );

dirname gets the directory name given in the passed string. If __FILE__ returns C:/wamp/www/vb4/plugins/includes/class_bootstrap.php, then dirname will return C:/wamp/www/vb4/plugins/includes. We then append /../ to it and then call realpath, which turns that relative .. into a real directory: C:/wamp/www/vb4/plugins

Phew.

From that point forward, CWD will operate as you expect. You can require_once CWD . '/includes/init.php' and it will correctly resolve to C:/wamp/www/vb4/plugins/includes/init.php

Also, this may sound stupid but "vb4" may be referring to vBulletin 4, in which case your plugin may already have access to the configuration information that it exposes, including handy things like paths. This may make this entire exercise unnecessary. I intentionally know nothing about vB, otherwise I would point you at their dev docs.

Create a closure around the File to capture the current file. Then you can get the filename.

An example: http://www.html5rocks.com/en/tutorials/file/dndfiles/#toc-reading-files

Closure to capture the file information.

function parseData(entries){
  for (var i=0; i<entries.length; i++) {
    reader.onloadend = (function(file) {
      return function(evt) {
        createListItem(evt, file)
      };
    })(entries[i]);
    reader.readAsText(entries[i]);
  }
}

And the called function gets an additional argument

function createListItem(evt, file) {
  console.log(evt.target.result)
  console.log(file.name);
}