How to get everything after a certain character?

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I've got a string and I'd like to get everything after a certain value. The string always starts off with a set of numbers and then an underscore. I'd like to get the rest of the string after the underscore. So for example if I have the following strings and what I'd like returned:

"123_String" -> "String"
"233718_This_is_a_string" -> "This_is_a_string"
"83_Another Example" -> "Another Example"

How can I go about doing something like this?

Answers

The strpos() finds the offset of the underscore, then substr grabs everything from that index plus 1, onwards.

$data = "123_String";    
$whatIWant = substr($data, strpos($data, "_") + 1);    
echo $whatIWant;

If you also want to check if the underscore character (_) exists in your string before trying to get it, you can use the following:

if (($pos = strpos($data, "_")) !== FALSE) { 
    $whatIWant = substr($data, $pos+1); 
}

Saturday, August 6, 2022

lzn-c7042b1992b0

You need a Ajax call to pass the JS value into php variable

JS Code will be (your js file)

var jsString="hello";
$.ajax({
    url: "ajax.php",
    type: "post",
    data: jsString
});

And in ajax.php (your php file) code will be

$phpString = $_POST['data'];     // assign hello to phpString

Thursday, November 10, 2022

mrvaldez

alert('my name is: <?php echo $man; ?>' );

Friday, August 19, 2022

rod_hyde

Do a find replace (replacing with nothing) this regex:

|.*

See https://regexr.com/3rq9m for explanation.

Tuesday, September 27, 2022

matteo_biondi

Just take the first portion of the split, and add '.zip' back:

s = 'test.zip.zyz'
s = s.split('.zip', 1)[0] + '.zip'

Alternatively you could use slicing, here is a solution where you don't need to add '.zip' back to the result (the 4 comes from len('.zip')):

s = s[:s.index('.zip')+4]

Or another alternative with regular expressions:

import re
s = re.match(r'^.*?.zip', s).group(0)

Wednesday, August 31, 2022

vovanium

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How to get everything after a certain character?

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