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I am designing my own MVC pattern to ease the process of creating homepages. My templating system needs my controller class to output my views. This means I have to output the file through a php function. I have been searching for some a while now and can't seem to find a solution.

How can I, through a PHP function, run a string representing some source code ("< ?", "< ?php", "? >" and so on) as php? Eval would not take my < ? signs (and I read that function is crap for some reason).

 Answers

2

You could execute the php code and collect the output like this:

ob_start();
include "template.phtml";
$out1 = ob_get_clean();

http://www.php.net/manual/de/function.ob-get-contents.php

Thursday, November 10, 2022
 
3

If you're validating the data on client side (i.e Javascript validation) which is absolutely not enough and not secure at all, You should implement it in View.

If you're validating data on server side, And your validation does not require application business logic (i.e you're not checking to see if the user has enough credit in his account), You should validate in the controller.

If the validation requires business logic, Implement it inside the model and call it via controller.

Postback validation is not good since it puts lots of pressure and delay, And the only advantage is to the programmer (not to be accounted).

You can use regex for most of validation, Which has the same syntax (almost) on PHP and JS.

Tuesday, December 20, 2022
2

The controller picks up the view variable in the url and using these determines which view needs to be used. It then sets the view to be used. The view then calls the model to fetch the data it requires and then passes this to the tmpl to be displayed.

Below is a simple setup of how this all works together:

components/com_test/controller.php

class TestController extends JController
{

  // default view
  function display() {
    // gets the variable some_var if it was posted or passed view GET.
    $var = JRequest::getVar( 'some_var' );
    // sets the view to someview.html.php
    $view = & $this->getView( 'someview', 'html' );
    // sets the template to someview.php
    $viewLayout  = JRequest::getVar( 'tmpl', 'someviewtmpl' );
    // assigns the right model (someview.php) to the view
    if ($model = & $this->getModel( 'someview' )) $view->setModel( $model, true );
    // tell the view which tmpl to use 
    $view->setLayout( $viewLayout );
    // go off to the view and call the displaySomeView() method, also pass in $var variable
    $view->displaySomeView( $var );
  }

}

components/com_test/views/someview/view.html.php

class EatViewSomeView extends JView
{

  function displaySomeView($var)  {
    // fetch the model assigned to this view by the controller
    $model = $this->getModel();
    // use the model to get the data we want to use on the frontend tmpl
    $data = $model->getSomeInfo($var);
    // assign model results to view tmpl
    $this->assignRef( 'data', $data );
    // call the parent class constructor in order to display the tmpl
    parent::display();
  }

}

components/com_test/models/someview.php

class EatModelSomeView extends JModel 
{

  // fetch the info from the database
  function getSomeInfo($var) {
    // get the database object
    $db = $this->getDBO();
    // run this query
    $db->setQuery("
      SELECT 
        *
      FROM #__some_table
      WHERE column=$var
    ");
    // return the results as an array of objects which represent each row in the results set from mysql select
    return $db->loadObjectList(); 
  }

}

components/com_test/views/someview/tmpl/someviewtmpl.php

// loop through the results passed to us in the tmpl
foreach($this->data as $data) {
  // each step here is a row and we can access the data in this row for each column by 
  // using $data->[col_name] where [col_name] is the name of the column you have in your db
  echo $data->column_name;
}
Tuesday, September 20, 2022
1

Looks like you in fact don't want to run PHP from Visual Code, but instead you're trying to get PHP to work at all.

  1. add in external php file which I created now

You're using short tags and that's ok, if your configuration allows it, however I would recommend using explicit PHP tags: <?php echo "My First PHP site in VSCode."; ?>

In my index.html file I referenced my php file like:

There's the problem. You're placing PHP code in a HTML file. PHP code in HTML files won't be (at least by default) executed. Change the filename from index.html to index.php.

That should do it.

Wednesday, November 16, 2022
5

one way is to use exec

http://ruby-doc.org/core/classes/Kernel.html#M005968

also `ls` or `cmd` works too (back tick)

Friday, September 16, 2022
 
zb
 
zb
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