Is there any way to test PHP locally without installing a server?

Question 1

I'm looking for something like http://phpfiddle.org/, but completely local. I don't want to commit to installing something as complex as Apache, then PHP on top of that, just to try out code when I'm offline. Is there anything that can run PHP 5.5 on the local machine without installing an entire server underneath it?

Question 2

There's no need for a server if using PHP 5.5+ - it has a built-in server (http://www.php.net/manual/en/features.commandline.webserver.php)

Just use:

$ cd ~/public_html
$ php -S localhost:8000

Question 3

Sure you just need to setup a local web server. Check out XAMPP: http://www.apachefriends.org/en/xampp.html

That will get you up and running in about 10 minutes.

There is now a way to run php locally without installing a server: https://.com/a/21872484/672229

Question 4

Updated :

This doesn't Work because :

$myphpvar = "<script>document.write(localStorage.getItem('myjsvar'));</script>";

Now your PHP $myphpvar variable contains :

  <script>document.write(localStorage.getItem('myjsvar'));</script>

when you echo then this is like :

echo "<script>document.write(localStorage.getItem('myjsvar'));</script>"

so this will show your Js variable,because it runs on your browser.

but when you do this in SQL : it look something like below :

$sql="INSERT INTO `pending` (`id`, `myfield`) VALUES ('', '<script>document.write(localStorage.getItem('myjsvar'));</script>')";

For Achieving this, you have to pass your localStorage value to URL,and get it on PHP or use AJAX to post!

window.location.href = window.location.href+"?local="+localStorage.getItem('myjsvar'));

Question 5

Since PHP does not have static constructors, you cannot automagically do something when a class is loaded. Your best bet is probably to print the message after the class definition (or use __autoload as Josh instructed, but that might require some reworking on your end).

class Foo
{
    /* stuff */
}

echo "Class Foo loaded from " . __FILE__ . "n";

EDIT Sorry to say, but PHP provides absolutely no hook to when a class is loaded or first instantiated, even in the dirtiest corners of its weird extensions. You will not be able to get away without either editing the classes' source files (and use my solution) or organize them in a conventional hierarchy to put them in (and use Josh's solution).

There is feature request #48546 that asks for a way to set a callback to when a file will be included but it's not going anywhere. Otherwise, people seem content with __autoload.

At best, you may call get_declared_classes at any time and see what's already been loaded.

Question 6

Javascript solution (with involving jQuery, though this should be possible to do without it too):

<script type='text/javascript'>
    $(function(){
        var files = [
            'warning-large.png',
            'warning-large-corrupted.png',
            'http://www.example.com/none.gif',
            'http://sstatic.net//img/favicon.ico'
        ];
        for ( var n in files ) {
            var img = $('<img/>');
            img.error(function(){
                alert('error:n' + this.src);
            });
            img.load(function(){
                alert('success:n' + this.src);
            });
            img.attr('src', files[n]);
        }
    });
</script>

Is there any way to test PHP locally without installing a server?

Answers

php,local,testbed