Keep input value after refresh page

Question 1

I have a form with input field and this input contain a drop down menu read information from database. If the user enters value and when he arrives to the drop menu he doesn't find what he wants he go to another page to add this info to the drop down menu and then go to the first page to continue enter the information. How can I keep this information if he goes to another page to add info to drop menu and how can after adding the info to drop menu find this info without refresh and without submit.

This is the first page with the form

<form name='' method='post' action='<?php $_PHP_SELF ?>'>
<input name='txt_name' id='' type='text'>

This drop menu read from database

 <select id="groups" name="txt_label" class="form-control">
   ';?>
     <?php 
    $sql=mysqli_query($conn,"select DISTINCT db_label from tbl_label")or die(mysqli_error($conn));
 echo'<option  value="">-- Select --</option>';
    while($row=mysqli_fetch_array($sql)){
        $label=$row['db_label'];
        echo "<option value='$label'>$label</option>"; 
    }echo'</select>';?><?php echo'
  </div>
</form>

Second form in another page

<form class="form-inline" role="form" name="form" method="post" action="';?><?php $_PHP_SELF ?><?php echo'">
    <div class="form-group">
    <label for="pwd">Label</label>
  <input id="txt_label" name="txt_label" type="text" placeholder="Label" class="form-control input-md">
  </div>
   <div class="form-group">
    <label for="pwd">Sub Label</label>
  <input id="txt_sublabel" name="txt_sublabel" type="text" placeholder="SubLabel" class="form-control input-md">
  </div>
   <input type="submit" name="addlabel" value="Add" class="btn btn-default">';

Question 2

EDIT: Keep value of more inputs

HTML:

<input type="text" id="txt_1" onkeyup='saveValue(this);'/> 
<input type="text" id="txt_2" onkeyup='saveValue(this);'/>

Javascript:

<script type="text/javascript">
        document.getElementById("txt_1").value = getSavedValue("txt_1");    // set the value to this input
        document.getElementById("txt_2").value = getSavedValue("txt_2");   // set the value to this input
        /* Here you can add more inputs to set value. if it's saved */

        //Save the value function - save it to localStorage as (ID, VALUE)
        function saveValue(e){
            var id = e.id;  // get the sender's id to save it . 
            var val = e.value; // get the value. 
            localStorage.setItem(id, val);// Every time user writing something, the localStorage's value will override . 
        }

        //get the saved value function - return the value of "v" from localStorage. 
        function getSavedValue  (v){
            if (!localStorage.getItem(v)) {
                return "";// You can change this to your defualt value. 
            }
            return localStorage.getItem(v);
        }
</script>

Question 3

This answer provides the necessary modifications to your code.

DISCLAIMER: Without seeing the exact install, be aware there may be a variety of factors that cause this to not work "as-is" in your installation. I do not know how your routes are set up, or if you are using Firebug or some other console to watch the ajax calls, but this should give you the building blocks:

First, change your php to output the array as a json-encoded string:

public function getCars(){
        $this->load->model('car_model');

        $this->form_validation->set_rules('carId', 'carId', 'trim|xss_clean');

        if($this->form_validation->run()){
            $carId = $this->input->post('carId');
            $carModels = $this->user_management_model->getCarModels($carId);
            // Add below to output the json for your javascript to pick up.
            echo json_encode($carModels);
            // a die here helps ensure a clean ajax call
            die();
        } else {
            echo "error";
        }   
}

Then, modify your script ajax call to have a success callback that gets the data and adds it to your dropdown:

function myFunction(obj)
  {
    $('#emptyDropdown').empty()
    var dropDown = document.getElementById("carId");
    var carId = dropDown.options[dropDown.selectedIndex].value;
    $.ajax({
            type: "POST",
            url: "/project/main/getcars",
            data: { 'carId': carId  },
            success: function(data){
                // Parse the returned json data
                var opts = $.parseJSON(data);
                // Use jQuery's each to iterate over the opts value
                $.each(opts, function(i, d) {
                    // You will need to alter the below to get the right values from your json object.  Guessing that d.id / d.modelName are columns in your carModels data
                    $('#emptyDropdown').append('<option value="' + d.ModelID + '">' + d.ModelName + '</option>');
                });
            }
        });
  }

Again - these are the building blocks. Use your browser console or a tool such as Firebug to watch the AJAX request, and the returned data, so you can modify as appropriate. Good luck!

Question 4

Set cookies: Save the checked element in cookieChecked

function validateSitec(){
if (document.getElementById('sitecheck').checked){
    $('#sitecheck').prop('checked', true);
    $('#closedmsg').slideDown();
    $.cookie("cookieChecked", "#sitecheck");
}else if(document.getElementById('closedmsg').checked){
    $('#closedmsg').slideUp();
    $("#sitecheck").removeProp("checked").checkboxradio("refresh");
    $.cookie("cookieChecked", "#closedmsg");
} else {
    $.cookie("cookieChecked","");
}
}

When page onload

 $(function(){
      var cookieChecked = $.cookie("cookieChecked");
      if(cookieChecked){
          $(cookieChecked).trigger("click");
      }
 })

I use the jquery cookie plugin : https://github.com/carhartl/jquery-cookie

Question 5

Your code works if you remove dataType: 'json', just tested it.

$('#save').click(function() {
  var tmp = JSON.stringify($('.dd').nestable('serialize'));
  // tmp value: [{"id":21,"children":[{"id":196},{"id":195},{"id":49},{"id":194}]},{"id":29,"children":[{"id":184},{"id":152}]},...]
  $.ajax({
    type: 'POST',
    url: 'save_categories.php',
    data: {'categories': tmp},
    success: function(msg) {
      alert(msg);
    }
  });
});

Question 6

In the Intel System Programming guide, chapter 6.5, it says

Faults — A fault is an exception that can generally be corrected and that, once corrected, allows the program to be restarted with no loss of continuity. When a fault is reported, the processor restores the machine state to the state prior to the beginning of execution of the faulting instruction. The return address (saved contents of the CS and EIP registers) for the fault handler points to the faulting instruction, rather than to the instruction following the faulting instruction.

A page fault is classified as a fault (no surprises there), so when a page fault happened you're in the state "before it ever happened" - well not really, because you're in the fault handler (so EIP and ESP are definitely different, also CR2 contains the address), but when you return it'll be the state before the ever happened, only with changes made by the handler (so, put there page there, or kill the process)

Keep input value after refresh page

Answers

javascript,php,jquery,ajax