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So I wonder if it is possible to get a variable from a specific php-file when the variable-name is used in multiple php-file. An example is this:

  <?php echo $var1; ?>

page1.php has $var1 = 'page1' page2.php has $var1 = 'page2'

footer.php should have <a href="">$var1 from page1</a><a href="">$var1 from page2</a>

Ok the example is a bit abstract, but as short as I can make it. I think you get what I am getting at! So it is the in the footer I am after! Got any solutions?



You can, but the variable in your last include will overwrite the variable in your first one:


$var = 'test';


$var = 'tester';


include 'myfile.php';
echo $var;

include 'mysecondfile.php';
echo $var;




I suggest using different variable names.

Friday, August 12, 2022

Here's what worked best for me when trying to script this (in case anyone else comes across this like I did):

$ pecl -d php_suffix=5.6 install <package>
$ pecl uninstall -r <package>

$ pecl -d php_suffix=7.0 install <package>
$ pecl uninstall -r <package>

$ pecl -d php_suffix=7.1 install <package>
$ pecl uninstall -r <package>

The -d php_suffix=<version> piece allows you to set config values at run time vs pre-setting them with pecl config-set. The uninstall -r bit does not actually uninstall it (from the docs):

vagrant@homestead:~$ pecl help uninstall
pecl uninstall [options] [channel/]<package> ...
Uninstalls one or more PEAR packages.  More than one package may be
specified at once.  Prefix with channel name to uninstall from a
channel not in your default channel (

  -r, --register-only
        do not remove files, only register the packages as not installed

The uninstall line is necessary otherwise installing it will remove any previously installed version, even if it was for a different PHP version (ex: Installing an extension for PHP 7.0 would remove the 5.6 version if the package was still registered as installed).

Monday, December 12, 2022

Please try with this

<script type="text/javascript">     
 function test() {
        url: 'moslem.php',
        type: 'POST',
        success: function(data) {
 $(document).ready(function() {
   setTimeout( test, 1000);    

No Need to pass the data parameter into ajax. And php file will remain same as before post.

  $chaine = "hello!"; 
  echo $chaine;
Tuesday, November 29, 2022

Change it

 $image = '$_GET[image_url]'; 


 $image = $_GET['image']; 
Sunday, November 20, 2022

Never used any of those, but they look interesting..

Take a look at Gearman as well.. more overhead in systems like these but you get other cool stuff :) Guess it depends on your needs ..

Friday, November 11, 2022
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