I want to be able to convert big ints into their full string derivatives.
For example.
$bigint = 9999999999999999999;
$bigint_string = (string) $bigint;
var_dump($bigint_string);
outputs
string(7) "1.0e+19"
but i need
string(19) "9999999999999999999"
Please don't tell me that I should just originally set the $bigint value as a string. That is not an option. I really am stuck and don't know if it is even possible?
You need a Ajax call to pass the JS value into php variable
JS Code will be (your js file)
var jsString="hello";
$.ajax({
url: "ajax.php",
type: "post",
data: jsString
});
And in ajax.php (your php file) code will be
$phpString = $_POST['data']; // assign hello to phpString
printf and friends will do this:
<?php
$awb = 2.01421700079E+14;
$str = sprintf("%d", $awb);
var_dump($str);
Output:
string(15) "201421700079000"
There obviously isn't enough information in your original number to get any more precision than that.
Use the strconv package's Itoa function.
For example:
package main
import (
"strconv"
"fmt"
)
func main() {
t := strconv.Itoa(123)
fmt.Println(t)
}
You can concat strings simply by +'ing them, or by using the Join function of the strings package.
You actually should ensure that you type what you mean:
Is not a PHP integer but float:
If you would have done
You would have set an integer in fact, but it would not be the number you might have expected:
It's no problem at all to turn that into string as you might have guessed. So take care when you write numbers into code that you actually write what you mean.
See this line again:
try to understand what you have actually written. It's not an integer at all because PHP will turn it into a float. See Example #4 Integer overflow on a 64-bit system in the integer manual page.
If you need higher precision, checkout GNU Multiple Precision, it might have what you're looking for. However, this won't change how to write numbers in PHP:
Output: