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Is there an approach for recursively merging arrays, in the same way as PHP's array_merge_recursive() function does, except that integer keys are treated the same as string keys?

(It's important for the process that the keys remain parse-able as integers.)

For example:

$a = array(
    'a' => array(1)
);
$b = array(
    'a' => array(2, 3)
);
var_dump(array_merge_recursive($a, $b));

Will merge the on the "a" key and output, as expected, the following:

array(1) {
    ["a"] => array(3) {
        [0] => int(1)
        [1] => int(2)
        [2] => int(3)
    }
}

However, when using integers for keys (even when as a string):

$a = array(
    '123' => array(1)
);
$b = array(
    '123' => array(2, 3)
);
var_dump(array_merge_recursive($a, $b));

array_merge_recursive() will return:

array(2) {
    [0] => array(3) {
        [0] => int(1)
    }
    [1] => array(2) {
        [0] => int(2)
        [1] => int(3)
    }
}

Instead of the much desired:

array(1) {
    ["123"] => array(3) {
        [0] => int(1)
        [1] => int(2)
        [2] => int(3)
    }
}

Thoughts?

 Answers

1

you can prefix the array keys with a short string:

function addPrefix($a) {
    return '_' . $a;
}
# transform keys
$array1 = array_combine(array_map('addPrefix', array_keys($array1)), $array1);
$array2 = array_combine(array_map('addPrefix', array_keys($array2)), $array2);
# call array_combine
$array = array_merge_recursive($array1, $array2);
# reverse previous operation  
function stripPrefix($a) {
     return substr($a, 1);
}
$array = array_combine(array_map('stripPrefix', array_keys($array)), $array)     
Tuesday, November 29, 2022
 
4

You need to iterate over your results, adding a new entry to the output when you encounter a new team, or updating the points value when you find the same team again. This is most easily done by initially indexing the output by the team name, and then using array_values to re-index the array numerically:

$teams = array();
foreach ($results as $result) {
    $team = $result['team'];
    if (!isset($teams[$team])) {
        $teams[$team] = array('team' => $team, 'points' => $result['punti']);
    }
    else {
        $teams[$team]['points'] += $result['punti'];
    }
}
$teams = array_values($teams);
print_r($teams);

Output (for your sample data):

Array
(
    [0] => Array
        (
            [team] => Red Bull Racing
            [points] => 418
        )
    [1] => Array
        (
            [team] => Scuderia Ferrari
            [points] => 353
        )
    [2] => Array
        (
            [team] => Mercedes-AMG
            [points] => 516
        )
    [3] => Array
        (
            [team] => Racing Point F1
            [points] => 147
        )
    [4] => Array
        (
            [team] => Haas F1
            [points] => 127
        )
)

Demo on 3v4l.org

Friday, August 12, 2022
 
2

Yes, but not with that version of the constructor. You can do this:

>>> dict([(1, 2), (3, 4)])
{1: 2, 3: 4}

There are several different ways to make a dict. As documented, "providing keyword arguments [...] only works for keys that are valid Python identifiers."

Tuesday, August 16, 2022
5

Like @HotLicks said, when you convert objects to JSON, the key part of the JSON map will be returned as a String. I don't believe there's any way to move around this behavior. I'd also steer clear of using integers as keys in your map, if the intended behavior is as a JSON map. Instead, I'd do something like:

map.put("identifier", 1);
map.put("value", "sample");

It's a little bit more verbose, but it's also easier to see how that translates to JSON.

Sunday, December 4, 2022
3

You can do it like this, do the calculation from the innermost of the array. Check the demo.

<?php
function f(&$array)
{
    foreach($array as $k => &$v)
    {
        if(is_array($v))
        {
            if(count($v) == count($v, 1))
            {
                unset($array[$k]);
                if($k == 'sum')
                {
                    $v =  array_sum($v);
                    $array[] = $v;

                }elseif($k == 'multiply'){
                    $v = array_product($v);
                    $array[] = $v;
                }else{

                    foreach($v as $vv)
                        $array[] = $vv;
                }
            }else
                f($v);
        }
    }
}

while(count($array) != count($array, 1))
{
    f($array);
}

print_r($array);

Noteļ¼š

traverse array from outer to inner
traverse array from inner to outer

Monday, November 14, 2022
 
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