POST data to a URL in PHP

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How can I send POST data to a URL in PHP (without a form)?

I'm going to use it for sending a variable to complete and submit a form.

Answers

If you're looking to post data to a URL from PHP code itself (without using an html form) it can be done with curl. It will look like this:

$url = 'http://www.someurl.com';
$myvars = 'myvar1=' . $myvar1 . '&myvar2=' . $myvar2;

$ch = curl_init( $url );
curl_setopt( $ch, CURLOPT_POST, 1);
curl_setopt( $ch, CURLOPT_POSTFIELDS, $myvars);
curl_setopt( $ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt( $ch, CURLOPT_HEADER, 0);
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, 1);

$response = curl_exec( $ch );

This will send the post variables to the specified url, and what the page returns will be in $response.

Saturday, August 6, 2022

kek0-a905e74b3f43

you would need 2 forms on your page, one form that posts back to index.php and a second form that posts to paypal

after the first form posts back to index.php, echo javascript in the body tag to submit the paypal form when it loads

    <?php
   if(isset($_POST['mydatafield'])){

        do database stuff

        $LOAD = 'document.paypal.submit();';
    }
    ?>
    <body onload="<?php echo $LOAD ?>">
    <form name="paypal" action="paypal.com?yadayada">
    paypal fields
    </form>
    <form name="myform" action="index.php">
    your form stuff
    submit button
    </form>

Sunday, September 18, 2022

christopher_rogers

Your post data is JSON so use json_decode to turn it into an array containing anobject and access the object_id property

$rawPostData = file_get_contents('php://input');
$json = json_decode($rawPostData);
$json = $json[0];
$all = date("F j, Y, g:i a") . " " . $json->object_id. "rn";
file_put_contents("Activity.log", $all, FILE_APPEND);

Monday, October 3, 2022

pope

I just found the solution and yea it was easier than I thought :)

so here is the solution:

string URI = "http://www.myurl.com/post.php";
string myParameters = "param1=value1&param2=value2&param3=value3";

using (WebClient wc = new WebClient())
{
    wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
    string HtmlResult = wc.UploadString(URI, myParameters);
}

it works like charm :)

Friday, December 23, 2022

aify

I used:

QByteArray postData;
postData.append("param1=string&");
postData.append("param2=string");

So & instead of newline after each parameter.

Sunday, October 30, 2022

progamer

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POST data to a URL in PHP

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