I would like to print an array to a file.
I would like the file to look exactly similar like how a code like this looks.
print_r ($abc); assuming $abc is an array.
Is there any one lines solution for this rather than regular for each look.
P.S - I currently use serialize but i want to make the files readable as readability is quite hard with serialized arrays.
After some debugging I found the solution myself.
The problem is, when User Entity was implementing the UserInterface, the user provider(actually the Doctrine, behind the scene) tried to Serializing the User object to store it in the session but because of the file that I assigned it to this class, it fails it's career!
To solve the problem, first I tried to fetch separate User object from database but unfortunately Doctrine gave me the exact reference of the User object again.(That's not a bug. Thanks to Doctrine. It's too smart to query as less as possible).
Second, I clone the User object myself in the controller before sending it to the UserType form, and then everything went well.
But that is not the best practice because you may have some other problems with registration, profile update or other scenarios that you may have with
Userclass.
In my application, I added another entity called Media and it stores the files with the file system and each entity like User which need some media (Like user avatar here), just have a ManyToOne relationship with this entity. In this case you can just save the name file as string in avatar field in User class.
You may have some other designs in your application but as I experienced, Do not assign a File field directly to the User entity which is implementing UserInterface!
The most obvious way to do this would be to print to a file object:
with open('out.txt', 'w') as f:
print('Filename:', filename, file=f) # Python 3.x
print >> f, 'Filename:', filename # Python 2.x
However, redirecting stdout also works for me. It is probably fine for a one-off script such as this:
import sys
orig_stdout = sys.stdout
f = open('out.txt', 'w')
sys.stdout = f
for i in range(2):
print('i = ', i)
sys.stdout = orig_stdout
f.close()
Since Python 3.4 there's a simple context manager available to do this in the standard library:
from contextlib import redirect_stdout
with open('out.txt', 'w') as f:
with redirect_stdout(f):
print('data')
Redirecting externally from the shell itself is another option, and often preferable:
./script.py > out.txt
Other questions:
What is the first filename in your script? I don't see it initialized.
My first guess is that glob doesn't find any bamfiles, and therefore the for loop doesn't run. Check that the folder exists, and print out bamfiles in your script.
Also, use os.path.join and os.path.basename to manipulate paths and filenames.
I ended up using BeautifulSoup directly. That is something lxml.html.soupparser uses for parsing HTML.
BeautifulSoup has a prettify method that does exactly what it says it does. It prettifies the HTML with proper indents and everything.
BeautifulSoup will NOT fix the HTML, so broken code, remains broken. But in this case, since the code is being generated by lxml, the HTML code should be at least semantically correct.
In the example given in my question, I will have to do this :
from BeautifulSoup import BeautifulSoup as bs
root = lh.tostring(sliderRoot) #convert the generated HTML to a string
soup = bs(root) #make BeautifulSoup
prettyHTML = soup.prettify() #prettify the html
Just put your serialized data in a string and save it with memcache,
$memcache->add('your_key', str, false, 30);
If the serailization generates binary data. You should base64 encode it yourself because PHP's binary encoding is very in-efficient.
Either
var_exportor setprint_rto return the output instead of printing it.Example from PHP manual
You can then save
$resultswithfile_put_contents. Or return it directly when writing to file: