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My web hosting said ImageMagic has been pre-installed on the server. I did a quick search for "ImageMagick" in the output of phpinfo() and I found nothing. I can't SSH in the server so is there a way in PHP I can verify the installation?



Try this:

//This function prints a text array as an html list.
function alist ($array) {  
  $alist = "<ul>";
  for ($i = 0; $i < sizeof($array); $i++) {
    $alist .= "<li>$array[$i]";
  $alist .= "</ul>";
  return $alist;
//Try to get ImageMagick "convert" program version number.
exec("convert -version", $out, $rcode);
//Print the return code: 0 if OK, nonzero if error. 
echo "Version return code is $rcode <br>"; 
//Print the output of "convert -version"    
echo alist($out); 
Wednesday, August 3, 2022

Your ImageMagick installation is not enough. You also need the Imagick package (possibly called php72-imagick or similar for home brew).

Imagick doesn't do the work itself, it is a native PHP extension for creating and modifying images using the ImageMagick API.

Try to search for the exact name of the package via brew search imagick.

Wednesday, November 16, 2022

You have to add in your php.ini file.

  • Location:

You can do some thing like this for the fastest way:

php -i | grep 'php.ini'

The result is like that:

Loaded Configuration File => /usr/local/lib/php.ini

Or call <?php phpinfo(); ?> from some php file to get this information :)

PS: Source

Monday, August 29, 2022

Imagick has a "setRegistry" method.

You can use it to set the imagemagick temp path like so:

$i = new Imagick();
$i->setRegistry('temporary-path', '/efs');
Monday, October 17, 2022

I am hopeless at PHP but something like this seems to work for me:

#!/usr/local/bin/php -f

   $info = getimagesize("input.jpg");

   // Calculate dimensions of output image

   // create white canvas
   $output = imagecreatetruecolor($canvasWidth, $canvasHeight);
   $background = imagecolorallocate($output, 255, 255, 255);
   imagefill($output, 0, 0, $background);

   // read in original image
   $orig = imagecreatefromjpeg("input.jpg");

   // copy left third to output image
   imagecopy($output, $orig,$padding,             $padding,             0, 0, $width/3, $height);
   // copy central third to output image
   imagecopy($output, $orig,2*$padding+$width/3,  $padding,      $width/3, 0, $width/3, $height);
   // copy right third to output image
   imagecopy($output, $orig,3*$padding+2*$width/3,$padding,    2*$width/3, 0, $width/3, $height);

   // save output image

If I start with this:

I get this as a result

I added the black outline afterwards so you can see the extent of the image.

Sunday, September 11, 2022
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